Fermat and Mersenne Primes
Fermat primes
Numbers of the form $F_n=2^{2^n}+1$ were studied by the outstanding French Mathematician Pierre de Fermat and are called Fermat Numbers.The first five Fermat Numbers are $F_0=3,F_1=5,F_2=17,F_3=257$ and $F_4=65537$
In order to find specific examples of primes, it seems reasonable to look at integers of the form $2^m \pm 1$, since many small primes such as $3,5,7,17,31\ldots$ have this form
If $2^m+1$ is prime then $m=2^n$ for some integers $n \ge 0$
Proof:we prove the contra positive that $m$ is not a power of 2 then $2^m + 1$ is not prime.If $m$ is not a power of 2, then $m$ has the form $2^nq$ for some odd $q>1$.Now the polynomial $f(t)=t^q+1$ has a root $t=-1$.So it is divisible by $t+1$.This is a proper factor since $q >1$, so putting $t=x^{2^n}$ we see that the polynomial $g(x)=f(x^{2^n})=x^m+1$ has a proper factor $x^{2^n}+1$.taking $x=2$ we see that $2^{2^n} +1$ is a proper factor of the integer $g(2)=2^m +1$, which cannot therefore be prime.
Numbers of the form $F_n=2^{2^n}+1$ are called Fermat Numbers, and those which are prime are called Fermat Primes.Fermat conjectured that $F_n$ is prime for every $n \ge 0$. For $n=0,\ldots , 4$, the numbers $F_n=3,5,17,257,65537$ are indeed prime.But in 1732 Euler showed that the next Fermat number
$$F_5=2^{2^5}+1=4294967297=641 \times 6700417$$
is composite.The Fermat numbers have been studied intensively, often with the aid of computers, but no further Fermat primes have been found. It is conceivable that there are further Fermat primes (perhaps infinitely many) which we have not yet found, but the evidence is not very convincing. These primes are important in geometry: in 1801 Gauss showed that a regular polygon with $k$ sides can be constructed by ruler-and-compass methods if and only if $k=2^ep_1\ldots p_r$, where $p_1..... p_r$, are distinct Fermat primes.
Lemma: Distinct Fermat Numbers $F_n$ are mutually coprime.
Proof:
Let $d=gcd(F_n,F_{m})$ be the greatest common divisors of two Fermat numbers $F_n$ and $F_{m}$.($F_n = 2^{2^n} + 1$ and $F_m = 2^{2^m} + 1$, where $m$ and $n$ are positive integers).Lets assume that $d>1$.
The difference between $F_n$ and $F_m$ is: $F_n−F_m=(2^{2^n}+1)−(2^{2^m}+1)$Mersenne Primes
Theorem:if $m>1$ and $a^m-1$ is prime, then $a=2$ and $m$ is prime.
Proof:
1.Assume $2^p−1$ is prime, where $p$ is a positive integer.3.Consider the factorization of $2^p-1$
5. It is also noted that
$2^p−1$ cannot be prime if $p$ is composite.
7.Thus, if $2^p−1$ is prime, then $p$ must also be prime.
Integers of the form $2^p-1$,where $p$ is prime, are called Mersenne numbers, after Mersenne who studied them in 1644; those which are Prime are called Mersenne Primes.
For the primes $p=2,3,5,7$, the Mersenne Numbers
$$M_p=3,7,31,127$$
are indeed Prime. But $M_{11}=2047=23*89$. So $M_p$ is not prime for every prime $p$.
Visit https://www.mersenne.org/ to know more about the latest Mersenne Primes.As in the case of Fermat Primes, it is not known whether there are finitely or infinitely many Mersenne Primes.
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